The rate constant for a second-order reaction is 0.54 M-1s-1. What is the half-life of this reaction if the initial concentration is 0.51 M?Group of answer choices3.6 s1.3 s2.8 s1.1 s0.94 s
Question
The rate constant for a second-order reaction is 0.54 M-1s-1. What is the half-life of this reaction if the initial concentration is 0.51 M?Group of answer choices3.6 s1.3 s2.8 s1.1 s0.94 s
Solution
The half-life (t1/2) for a second-order reaction can be calculated using the following formula:
t1/2 = 1 / (k[A]0)
where:
- k is the rate constant
- [A]0 is the initial concentration
Given in the problem, k = 0.54 M-1s-1 and [A]0 = 0.51 M.
Substituting these values into the formula, we get:
t1/2 = 1 / (0.54 M-1s-1 * 0.51 M) = 1 / 0.2754 s-1 = 3.63 s
So, the closest answer is 3.6 s.
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