This exercise is part of the ‘Lab 6’ exercise set. If you get stuck on this exercise, you can click here to skip to the next unfinished exercise in the set.AdvancedA slice expression, a_list[start:end], returns a new list with the elements from start to end - 1 of the list. Write a function slice_in_place(a_list, start, end), which takes as arguments a list and two indices, and modifies the argument list so that it is equal to the result of the slice expression a_list[start:end]. The function should not return any value.Make your slice_in_place function work with both positive and negative indices (like slicing does).The required output is:[2, 3][1, 2][][][6][]Your code1def slice_in_place(a_list, start, end):2 # TODO: implement this function3
Question
This exercise is part of the ‘Lab 6’ exercise set. If you get stuck on this exercise, you can click here to skip to the next unfinished exercise in the set.AdvancedA slice expression, a_list[start:end], returns a new list with the elements from start to end - 1 of the list. Write a function slice_in_place(a_list, start, end), which takes as arguments a list and two indices, and modifies the argument list so that it is equal to the result of the slice expression a_list[start:end]. The function should not return any value.Make your slice_in_place function work with both positive and negative indices (like slicing does).The required output is:[2, 3][1, 2][][][6][]Your code1def slice_in_place(a_list, start, end):2 # TODO: implement this function3
Solution
Here is a Python function that implements the slice_in_place functionality:
def slice_in_place(a_list, start, end):
# Handle negative indices
if start < 0:
start = len(a_list) + start
if end < 0:
end = len(a_list) + end
# Delete elements from the end to the start
del a_list[end:]
del a_list[:start]
This function first handles the case where the start or end indices are negative. In Python, a negative index -i is equivalent to the index len(a_list) - i, so we add len(a_list) to any negative index to get its equivalent positive index.
Then, the function deletes all elements after the end index and all elements before the start index. The order of these operations is important: if we deleted the elements before the start index first, then the end index would no longer point to the correct element.
This function modifies the input list in place, and does not return anything.
Similar Questions
A slice expression, a_list[start:end], returns a new list with the elements from start to end - 1 of the list. Write a function slice_in_place(a_list, start, end), which takes as arguments a list and two indices, and modifies the argument list so that it is equal to the result of the slice expression a_list[start:end]. The function should not return any value.The required output is:[2, 3][1, 2][][]Your code1def slice_in_place(a_list, start, end):2 # TODO: implement this function3 pass
Slice Operation will be performed on a list using which symbol?Options:(colon)-(hyphen).(dot)slice
What will be the output of the following code?t=(1,2,4,3,4,5,6,7,8)t[1:5](2,4,3,4) is the correct answer. Using the slice notation t[1:5], we extract a segment from the tuple t that begins at index 1 and extends up to, but does not include index 5. The resulting tuple is (2, 4, 3, 4), consisting of elements within that range.
The list method pop(position) removes the element in the given position from the list (read help(list.pop) or the on-line documentation).Write a function allbut(a_list, index), which takes as arguments a list and an index, and returns a new list with all elements of the argument list (in the order they were) except for the element at index. The argument list should not be modified by the function.The required output is:[1, 2, 4][1, 2, 3, 4][2, 4, 6, 7, 8][3, 2, 4, 6, 7, 8]Your code1def allbut(a_list, index):2 #TODO: implement this function3 pass
What is the slice expression that gives every third character of string s, starting with the last character and proceeding backward to the first?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.