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#06 bond makingThe following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely. Bond formation, being the opposite, releases the same amount of heat from the chemical system.Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946N-H 391 C≡N 891 *C=O in carbon dioxide 804 kJ/molCalculate the heat released from the system on formation of 1.00 mol of the compound, methylamine CH3NH2, from its individual atoms, 1 mol C, 5 mol H and 1 mol N. C  +  5 H  + 1 N  →  CH3NH2  methylamineQuestion 4Select one:a.2304 kJb.1109 kJc.762 kJd.2326 kJe.2021 kJ

Question

#06 bond makingThe following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely. Bond formation, being the opposite, releases the same amount of heat from the chemical system.Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946N-H 391 C≡N 891 *C=O in carbon dioxide 804 kJ/molCalculate the heat released from the system on formation of 1.00 mol of the compound, methylamine CH3NH2, from its individual atoms, 1 mol C, 5 mol H and 1 mol N. C  +  5 H  + 1 N  →  CH3NH2  methylamineQuestion 4Select one:a.2304 kJb.1109 kJc.762 kJd.2326 kJe.2021 kJ

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Solution

To solve this problem, we need to calculate the total energy released when the bonds in methylamine (CH3NH2) are formed.

The molecule CH3NH2 has the following bonds: 3 C-H bonds, 1 C-N bond, and 2 N-H bonds.

Using the given bond dissociation energies:

  • Energy released from the formation of 3 C-H bonds = 3 * 413 kJ/mol = 1239 kJ/mol
  • Energy released from the formation of 1 C-N bond = 1 * 305 kJ/mol = 305 kJ/mol
  • Energy released from the formation of 2 N-H bonds = 2 * 391 kJ/mol = 782 kJ/mol

Adding these up, the total energy released from the formation of 1 mol of CH3NH2 from its individual atoms is 1239 kJ/mol + 305 kJ/mol + 782 kJ/mol = 2326 kJ/mol.

So, the correct answer is d. 2326 kJ.

This problem has been solved

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