In 58x, the diference between protons and notronsnumber is 6. How many electrons does x2+ have?
Question
In 58x, the diference between protons and notronsnumber is 6. How many electrons does x2+ have?
Solution
To solve this problem, we need to follow these steps:
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In an atom, the number of protons is equal to the atomic number. In this case, the atomic number is 58, so there are 58 protons.
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The difference between the number of protons and neutrons is 6. This means there are 58 + 6 = 64 neutrons.
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In a neutral atom, the number of electrons is equal to the number of protons. So, in a neutral atom of this element, there would be 58 electrons.
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However, the atom is not neutral, it is a cation with a charge of +2 (X2+). This means it has lost 2 electrons.
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Therefore, the number of electrons in X2+ is 58 - 2 = 56 electrons.
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