A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?A. 20 yearsB. 22 yearsC. 24 yearsD. 26 years
Question
A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?A. 20 yearsB. 22 yearsC. 24 yearsD. 26 years
Solution
Let's denote the present age of the son as X.
According to the problem, the man is 24 years older than his son, so the man's present age is X + 24.
In two years, the son will be X + 2 and the man will be X + 24 + 2 = X + 26.
The problem states that in two years, the man's age will be twice the age of his son. So we can set up the equation:
X + 26 = 2 * (X + 2)
Solving this equation will give us the present age of the son.
X + 26 = 2X + 4
Subtract X from both sides:
26 = X + 4
Subtract 4 from both sides:
X = 22
So, the present age of the son is 22 years old. The correct answer is B. 22 years.
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