The probability is 0%.

Here's why:

Color blindness is an X-linked recessive trait. This means that a female (XX) would need two copies of the color blindness gene to be color blind, one on each X chromosome. A male (XY) only needs one copy, because he only has one X chromosome.

In this case, the male is not color blind, so he does not have the color blindness gene to pass on. The female is a carrier, which means she has one copy of the color blindness gene and one normal gene.

If they have a girl, she will receive one X chromosome from her father and one X chromosome from her mother. The X chromosome from her father does not carry the color blindness gene. The X chromosome from her mother could carry either the color blindness gene or the normal gene.

However, even if the daughter receives the color blindness gene from her mother, she will not be color blind because she also has a normal gene from her father. She would be a carrier, like her mother.

Therefore, the probability that a girl born to this couple will be color blind is 0%.

Question

The probability is 0%.

Here's why:

Color blindness is an X-linked recessive trait. This means that a female (XX) would need two copies of the color blindness gene to be color blind, one on each X chromosome. A male (XY) only needs one copy, because he only has one X chromosome.

In this case, the male is not color blind, so he does not have the color blindness gene to pass on. The female is a carrier, which means she has one copy of the color blindness gene and one normal gene.

If they have a girl, she will receive one X chromosome from her father and one X chromosome from her mother. The X chromosome from her father does not carry the color blindness gene. The X chromosome from her mother could carry either the color blindness gene or the normal gene.

However, even if the daughter receives the color blindness gene from her mother, she will not be color blind because she also has a normal gene from her father. She would be a carrier, like her mother.

Therefore, the probability that a girl born to this couple will be color blind is 0%.

Knowee AI · Accepted Answer

The probability is 0%.

Here's why:

Color blindness is an X-linked recessive trait. This means that a female (XX) would need two copies of the color blindness gene to be color blind, one on each X chromosome. A male (XY) only needs one copy, because he only has one X chromosome.

In this case, the male is not color blind, so he does not have the color blindness gene to pass on. The female is a carrier, which means she has one copy of the color blindness gene and one normal gene.

If they have a girl, she will receive one X chromosome from her father and one X chromosome from her mother. The X chromosome from her father does not carry the color blindness gene. The X chromosome from her mother could carry either the color blindness gene or the normal gene.

However, even if the daughter receives the color blindness gene from her mother, she will not be color blind because she also has a normal gene from her father. She would be a carrier, like her mother.

Therefore, the probability that a girl born to this couple will be color blind is 0%.

Color blindness is an X-linked recessive trait. A male that is not color-blind is crossed with a female that is a carrier for color blindness. If they have a girl, what is the probability she will be color-blind?Group of answer choices75%25%0%100%50%

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