Given the line L with equation9 y − x = 12(a) Find its gradient and y-intercept.(b) Sketch its graph
Question
Given the line L with equation9 y − x = 12(a) Find its gradient and y-intercept.(b) Sketch its graph
Solution
(a) To find the gradient and y-intercept, we first need to rearrange the equation into the form y = mx + c, where m is the gradient and c is the y-intercept.
The given equation is 9y - x = 12.
Let's rearrange it:
9y = x + 12
Divide through by 9 to isolate y:
y = 1/9x + 12/9
So, the gradient (m) is 1/9 and the y-intercept (c) is 12/9 or 4/3.
(b) To sketch the graph, you would start by marking the y-intercept (0, 4/3) on the y-axis. Since the gradient is positive, the line will be going upwards. The gradient 1/9 means that for every 9 units you move to the right along the x-axis, you move up 1 unit on the y-axis. So from the y-intercept, you could go to the point (9, 1) and draw a line through these two points to sketch the graph.
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