A proton is moving along the axis of a solenoid carrying a current. The magneticforce on proton will be:A. Radially inward ⃝ B. Radially outward ⃝C. Zero ⃝ D. Parallel to axis of solenoid
Question
A proton is moving along the axis of a solenoid carrying a current. The magneticforce on proton will be:A. Radially inward ⃝ B. Radially outward ⃝C. Zero ⃝ D. Parallel to axis of solenoid
Solution
The answer is C. Zero.
Here's why:
The magnetic field inside a long solenoid carrying current is uniform and parallel to the axis of the solenoid. The force on a charged particle moving in a magnetic field is given by the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.
In this case, the proton is moving along the axis of the solenoid, so the angle θ between the velocity of the proton and the magnetic field is 0 degrees. The sine of 0 degrees is 0, so the force on the proton is zero. Therefore, the magnetic force on the proton is zero.
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