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There are 9 students in a class. The teacher chooses 2 students to go to the library. The order in which they are chosen does not matter. How many ways are there to choose the students?A.72B.504C.36D.81

Question

There are 9 students in a class. The teacher chooses 2 students to go to the library. The order in which they are chosen does not matter. How many ways are there to choose the students?A.72B.504C.36D.81

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Solution

This is a combination problem. The formula for combinations is C(n, k) = n! / [k!(n-k)!], where n is the total number of options, k is the number of options chosen, and "!" denotes factorial.

In this case, n = 9 (the total number of students) and k = 2 (the number of students chosen).

So, we have C(9, 2) = 9! / [2!(9-2)!] = 98 / (21) = 36.

So, the answer is C.36.

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