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The average height of an American adult is 1.70 m. When an individual of this height is standing, by how much will the blood pressure at the bottom of the feet differ from the blood pressure at the top of the head? (Densityblood = 1060 kg/m3)A.2000 PaB.6000 PaC.10000 PaD.18000 Pa

Question

The average height of an American adult is 1.70 m. When an individual of this height is standing, by how much will the blood pressure at the bottom of the feet differ from the blood pressure at the top of the head? (Densityblood = 1060 kg/m3)A.2000 PaB.6000 PaC.10000 PaD.18000 Pa

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Solution

To solve this problem, we need to use the formula for pressure difference in a fluid column, which is given by:

ΔP = ρgh

where:

  • ΔP is the pressure difference,
  • ρ is the density of the fluid (in this case, blood),
  • g is the acceleration due to gravity, and
  • h is the height difference.

Given:

  • ρ = 1060 kg/m³ (density of blood),
  • g = 9.81 m/s² (acceleration due to gravity), and
  • h = 1.70 m (height of an average American adult).

Substituting these values into the formula, we get:

ΔP = 1060 kg/m³ * 9.81 m/s² * 1.70 m = 17614.2 Pa

Rounding this to the nearest whole number, we get ΔP = 17614 Pa.

However, this value is not listed in the options. The closest option to this value is D. 18000 Pa. Therefore, the answer is D. 18000 Pa.

This problem has been solved

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