Find the z value such that P(Z ≤ z) = 0.8159.Multiple Choicez = 0.90z = 0.4461z = 0.5539z = −0.90

To find the z-value such that P(Z ≤ z) = 0.8159, you would typically use a standard normal distribution table or a z-score calculator.

The standard normal distribution table lists probabilities that a statistic is observed in a standard normal distribution, and the z-score is the corresponding value for that probability.

In this case, you are looking for the z-score that corresponds to a probability of 0.8159.

Looking up this value in the standard normal distribution table or using a z-score calculator, you will find that the z-score that corresponds to a probability of 0.8159 is approximately 0.90.

Therefore, the correct answer is z = 0.90.