Phenylmagnesium bromide reacts with methanol to give
Question
Phenylmagnesium bromide reacts with methanol to give
Solution
Phenylmagnesium bromide reacts with methanol to produce benzene and magnesium bromide methoxide. Here's the step-by-step process:
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Phenylmagnesium bromide (C6H5MgBr) is a Grignard reagent, which is highly reactive and can react with a variety of substances. In this case, it's reacting with methanol (CH3OH).
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The reaction between these two substances is a nucleophilic addition reaction. The phenylmagnesium bromide acts as a nucleophile, meaning it donates a pair of electrons. The methanol acts as an electrophile, accepting the pair of electrons.
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The magnesium atom in the phenylmagnesium bromide forms a bond with the oxygen atom in the methanol. This breaks the bond between the carbon and oxygen atoms in the methanol, releasing a hydrogen atom.
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The released hydrogen atom then bonds with the bromine atom, which was previously bonded to the magnesium atom. This forms hydrogen bromide (HBr).
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The remaining atoms (a phenyl group and a magnesium-oxygen bond) form benzene (C6H6) and magnesium bromide methoxide (MgBrOCH3).
So, the final products of this reaction are benzene and magnesium bromide methoxide.
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METHANOL EXTRACTION
Dibromoethane and potassium iodide react in methanol (the solvent) according to the equation: C2H4Br2 + 3KI → C2H4 + 2KBr + KI3 The initial rate of this reaction was determined in a series of experiments at 65 °C, giving the data below:Experiment [C2H4Br2] /mol L–1 [KI] /mol L–1 +(d[KI3]/dt) /mol L–1s–11 0.426 1.909 0.006272 0.426 2.864 0.009413 1.067 1.909 0.0157 a) Determine the order of the reaction with respect to C2H4Br2Multiple choice 1 Question 10123b) Determine the order of the reaction with respect to KIMultiple choice 2 Question 10123c) Determine the value of the rate constant and select the appropriate units for it.
Name the product formed when methyl bromide is treated with sodium and ether
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