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A wooden block of volume 5.00 x 104 m3 floats partially submerged in water, and a small steel object of mass m is placed on top of the block. When m = 0.25 kg, the system is in equilibrium and the top of the wooden block is at the level of the water. What is the density of the wood?a.500 kg.m-3b.1500 kg.m-3c.1000 kg.m-3d.800 kg.m-3

Question

A wooden block of volume 5.00 x 104 m3 floats partially submerged in water, and a small steel object of mass m is placed on top of the block. When m = 0.25 kg, the system is in equilibrium and the top of the wooden block is at the level of the water. What is the density of the wood?a.500 kg.m-3b.1500 kg.m-3c.1000 kg.m-3d.800 kg.m-3

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Solution

The density of an object is defined as its mass divided by its volume. In this case, we know that the wooden block is floating in water, which means that the weight of the water displaced by the block is equal to the weight of the block itself. This is known as Archimedes' principle.

The weight of the water displaced by the block is equal to the volume of the block multiplied by the density of water (which is 1000 kg/m^3) and the acceleration due to gravity (which is approximately 9.8 m/s^2).

So, the weight of the water displaced is:

Weight_water = Volume_block * Density_water * g Weight_water = 5.00 x 10^4 m^3 * 1000 kg/m^3 * 9.8 m/s^2 Weight_water = 4.9 x 10^8 N

Since the system is in equilibrium, the weight of the water displaced is equal to the weight of the block plus the weight of the steel object. The weight of the steel object is its mass multiplied by the acceleration due to gravity:

Weight_steel = m * g Weight_steel = 0.25 kg * 9.8 m/s^2 Weight_steel = 2.45 N

So, the weight of the block is:

Weight_block = Weight_water - Weight_steel Weight_block = 4.9 x 10^8 N - 2.45 N Weight_block = 4.9 x 10^8 N

The density of the block is its weight divided by its volume and the acceleration due to gravity:

Density_block = Weight_block / (Volume_block * g) Density_block = 4.9 x 10^8 N / (5.00 x 10^4 m^3 * 9.8 m/s^2) Density_block = 1000 kg/m^3

So, the density of the wood is 1000 kg/m^3, which corresponds to option c.

This problem has been solved

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