To solve this problem, we first need to find out how many students play either basketball or baseball or both.

We know that 18 students play basketball, 8 play baseball, and 9 play neither.

So, the number of students who play either basketball or baseball or both is 30 (total students) - 9 (those who play neither) = 21 students.

Next, we need to find out how many students play both sports.

We know that 18 students play basketball and 8 play baseball. If none of these students were the same, we would have 18 + 8 = 26 students.

But we know that only 21 students play a sport, so the difference, 26 - 21 = 5, must be the students who play both sports.

So, 5 students play both basketball and baseball.

The probability that a student chosen randomly from the class plays both basketball and baseball is therefore 5 (students who play both) / 30 (total students) = 1/6.

Question

To solve this problem, we first need to find out how many students play either basketball or baseball or both.

We know that 18 students play basketball, 8 play baseball, and 9 play neither.

So, the number of students who play either basketball or baseball or both is 30 (total students) - 9 (those who play neither) = 21 students.

Next, we need to find out how many students play both sports.

We know that 18 students play basketball and 8 play baseball. If none of these students were the same, we would have 18 + 8 = 26 students.

But we know that only 21 students play a sport, so the difference, 26 - 21 = 5, must be the students who play both sports.

So, 5 students play both basketball and baseball.

The probability that a student chosen randomly from the class plays both basketball and baseball is therefore 5 (students who play both) / 30 (total students) = 1/6.

Knowee AI · Accepted Answer

To solve this problem, we first need to find out how many students play either basketball or baseball or both.

We know that 18 students play basketball, 8 play baseball, and 9 play neither.

So, the number of students who play either basketball or baseball or both is 30 (total students) - 9 (those who play neither) = 21 students.

Next, we need to find out how many students play both sports.

We know that 18 students play basketball and 8 play baseball. If none of these students were the same, we would have 18 + 8 = 26 students.

But we know that only 21 students play a sport, so the difference, 26 - 21 = 5, must be the students who play both sports.

So, 5 students play both basketball and baseball.

The probability that a student chosen randomly from the class plays both basketball and baseball is therefore 5 (students who play both) / 30 (total students) = 1/6.

In a certain Algebra 2 class of 30 students, 18 of them play basketball and 8 of them play baseball. There are 9 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

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