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The cost of an apple is twice that of a banana and the cost of a banana is 25% less than that of a guava. If the cost of each type of fruit increases by 10%, then the percentage increases in cost of 4 bananas, 2 apples and 3 guavas is?

Question

The cost of an apple is twice that of a banana and the cost of a banana is 25% less than that of a guava. If the cost of each type of fruit increases by 10%, then the percentage increases in cost of 4 bananas, 2 apples and 3 guavas is?

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Solution

To solve this problem, we first need to establish the initial cost of each fruit. Let's assume the cost of a guava is $1.

  1. Since the cost of a banana is 25% less than that of a guava, the cost of a banana is $0.75.
  2. The cost of an apple, which is twice that of a banana, is $1.50.

Next, we calculate the total initial cost of 4 bananas, 2 apples, and 3 guavas:

  1. 4 bananas cost 4 * 0.75=0.75 = 3.00
  2. 2 apples cost 2 * 1.50=1.50 = 3.00
  3. 3 guavas cost 3 * 1.00=1.00 = 3.00

So, the total initial cost is 3.00+3.00 + 3.00 + 3.00=3.00 = 9.00

Now, let's calculate the new cost if the cost of each type of fruit increases by 10%:

  1. The new cost of a banana is 0.751.10=0.75 * 1.10 = 0.825
  2. The new cost of an apple is 1.501.10=1.50 * 1.10 = 1.65
  3. The new cost of a guava is 1.001.10=1.00 * 1.10 = 1.10

The total new cost of 4 bananas, 2 apples, and 3 guavas is:

  1. 4 bananas cost 4 * 0.825=0.825 = 3.30
  2. 2 apples cost 2 * 1.65=1.65 = 3.30
  3. 3 guavas cost 3 * 1.10=1.10 = 3.30

So, the total new cost is 3.30+3.30 + 3.30 + 3.30=3.30 = 9.90

Finally, to find the percentage increase in cost, we subtract the initial total cost from the new total cost, divide by the initial total cost, and multiply by 100:

Percentage increase = ((9.909.90 - 9.00) / $9.00) * 100 = 10%

So, the percentage increase in cost of 4 bananas, 2 apples, and 3 guavas is 10%.

This problem has been solved

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