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Calculate the volume in liters of a /0.0112gL zinc oxalate solution that contains 100.mg of zinc oxalate ZnC2O4.Be sure your answer has the correct number of significant digits.

Question

Calculate the volume in liters of a /0.0112gL zinc oxalate solution that contains 100.mg of zinc oxalate ZnC2O4.Be sure your answer has the correct number of significant digits.

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Solution

First, we need to convert the concentration of the zinc oxalate solution from g/L to mg/L since the amount of zinc oxalate we have is given in mg.

1 g = 1000 mg

So, 0.0112 g/L = 0.0112 * 1000 mg/L = 11.2 mg/L

Next, we use the formula for concentration which is:

Concentration = Amount of Solute / Volume of Solution

We can rearrange this formula to solve for the volume of the solution:

Volume of Solution = Amount of Solute / Concentration

Substituting the given values:

Volume of Solution = 100 mg / 11.2 mg/L = 8.93 L

So, the volume of the 0.0112 g/L zinc oxalate solution that contains 100 mg of zinc oxalate is approximately 8.93 liters.

This problem has been solved

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