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Solve analytically and graphically the following systems of equations of linear/non-linear.3) y = 2x^2 - 4x + 5 and y = -2x + 94) 3x^2 - y^2 = 1 and x^2 - y^2 = - 1

Question

Solve analytically and graphically the following systems of equations of linear/non-linear.3) y = 2x^2 - 4x + 5 and y = -2x + 94) 3x^2 - y^2 = 1 and x^2 - y^2 = - 1

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Solution

To solve the given systems of equations analytically and graphically, we will follow these steps:

  1. y = 2x^2 - 4x + 5 and y = -2x + 9

Analytical Solution: Step 1: Set the two equations equal to each other: 2x^2 - 4x + 5 = -2x + 9

Step 2: Rearrange the equation to standard form: 2x^2 - 4x + 2x - 4 = 9 - 5 2x^2 - 2x - 4 = 4

Step 3: Simplify the equation: 2x^2 - 2x - 8 = 0

Step 4: Solve the quadratic equation using factoring, completing the square, or the quadratic formula. In this case, we will use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values a = 2, b = -2, and c = -8, we get: x = (-(-2) ± √((-2)^2 - 4(2)(-8))) / (2(2)) x = (2 ± √(4 + 64)) / 4 x = (2 ± √68) / 4 x = (2 ± 2√17) / 4 x = (1 ± √17) / 2

Step 5: Substitute the values of x back into one of the original equations to find the corresponding y-values. Let's use the equation y = -2x + 9: For x = (1 + √17) / 2: y = -2((1 + √17) / 2) + 9 y = -1 - √17 + 9 y = 8 - √17

For x = (1 - √17) / 2: y = -2((1 - √17) / 2) + 9 y = -1 + √17 + 9 y = 8 + √17

Therefore, the solutions to the system of equations are: (x, y) = ((1 + √17) / 2, 8 - √17) and ((1 - √17) / 2, 8 + √17)

Graphical Solution: To graphically solve the system of equations, we will plot the two equations on a coordinate plane and find the points of intersection.

For the first equation, y = 2x^2 - 4x + 5, we can plot points by substituting different x-values and calculating the corresponding y-values.

For the second equation, y = -2x + 9, we can also plot points by substituting different x-values and calculating the corresponding y-values.

By plotting the points and observing the graph, we can find the points of intersection, which represent the solutions to the system of equations.

  1. 3x^2 - y^2 = 1 and x^2 - y^2 = -1

Analytical Solution: Step 1: Set the two equations equal to each other: 3x^2 - y^2 = 1 x^2 - y^2 = -1

Step 2: Subtract the second equation from the first equation to eliminate the y^2 term: (3x^2 - y^2) - (x^2 - y^2) = 1 - (-1) 2x^2 = 2 x^2 = 1 x = ±1

Step 3: Substitute the values of x back into one of the original equations to find the corresponding y-values. Let's use the equation x^2 - y^2 = -1: For x = 1: 1 - y^2 = -1 y^2 = 2 y = ±√2

For x = -1: (-1) - y^2 = -1 y^2 = 0 y = 0

Therefore, the solutions to the system of equations are: (x, y) = (1, √2), (1, -√2), (-1, 0)

Graphical Solution: To graphically solve the system of equations, we will plot the two equations on a coordinate plane and find the points of intersection.

For the first equation, 3x^2 - y^2 = 1, we can plot points by substituting different x-values and calculating the corresponding y-values.

For the second equation, x^2 - y^2 = -1, we can also plot points by substituting different x-values and calculating the corresponding y-values.

By plotting the points and observing the graph, we can find the points of intersection, which represent the solutions to the system of equations.

This problem has been solved

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