Let's denote the smaller number as x. Then the next consecutive number is x + 1.

According to the problem, the difference of the squares of these two numbers is 93. This can be written as:

(x + 1)^2 - x^2 = 93

Expanding and simplifying this equation gives:

x^2 + 2x + 1 - x^2 = 93
2x + 1 = 93
2x = 92
x = 46

So, the smaller number is 46. Therefore, the answer is C. 46.

Question

Let's denote the smaller number as x. Then the next consecutive number is x + 1.

According to the problem, the difference of the squares of these two numbers is 93. This can be written as:

(x + 1)^2 - x^2 = 93

Expanding and simplifying this equation gives:

x^2 + 2x + 1 - x^2 = 93
2x + 1 = 93
2x = 92
x = 46

So, the smaller number is 46. Therefore, the answer is C. 46.

Knowee AI · Accepted Answer

Let's denote the smaller number as x. Then the next consecutive number is x + 1.

According to the problem, the difference of the squares of these two numbers is 93. This can be written as:

(x + 1)^2 - x^2 = 93

Expanding and simplifying this equation gives:

x^2 + 2x + 1 - x^2 = 93
2x + 1 = 93
2x = 92
x = 46

So, the smaller number is 46. Therefore, the answer is C. 46.

If the difference of squares of two consecutive numbers is 93, then determine the smaller number. Ops: A. 48 B. 45 C. 46 D. 47