Which regular grammar generates the language consisting of strings with zero or more occurrences of "a" followed by "b"? Options : S -> ab | aS | ε S -> a | b | aS S -> ab | aS none
Question
Which regular grammar generates the language consisting of strings with zero or more occurrences of "a" followed by "b"?
Options : S -> ab | aS | ε S -> a | b | aS S -> ab | aS none
Solution
The correct answer is "S -> ab | aS | ε". This regular grammar generates the language consisting of strings with zero or more occurrences of "a" followed by "b".
Here's why:
- "S -> ab" generates a string with one occurrence of "a" followed by "b".
- "S -> aS" allows for the generation of multiple occurrences of "a" before a "b" is appended. This is because "S" can be replaced by "ab" or "aS" again, allowing for multiple "a"s to be generated.
- "S -> ε" allows for the generation of a string with no "a"s, only "b". The symbol "ε" represents an empty string.
The other options do not correctly generate the language as described.
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