Given Vs = 23 voltsR = 12 ohmsL = 4.2 mHC = 1.1 microfaradsFrequency, F = 1000HzCalculate the phase of the phasor current I in radians.Choose a value of phase which is between -pi and +pi.

Step 1: Convert the inductance from millihenries to henries and the capacitance from microfarads to farads.

1 millihenry = 1e-3 henries So, L = 4.2 millihenries = 4.2 * 1e-3 = 0.0042 henries

1 microfarad = 1e-6 farads So, C = 1.1 microfarads = 1.1 * 1e-6 = 0.0000011 farads

Step 2: Calculate the reactance (Xl) of the inductor and the reactance (Xc) of the capacitor using the formulas:

Xl = 2 * π * F * L Xc = 1 / (2 * π * F * C)

where: π = 3.14159 (approx) F = frequency = 1000 Hz L = inductance = 0.0042 henries C = capacitance = 0.0000011 farads

Substituting the values, we get:

Xl = 2 * 3.14159 * 1000 * 0.0042 = 26.39 ohms (approx) Xc = 1 / (2 * 3.14159 * 1000 * 0.0000011) = 144.51 ohms (approx)

Step 3: Calculate the phase angle (θ) of the phasor current. The phase angle is the arctangent of the ratio of the difference between the reactances (Xl and Xc) to the resistance (R).

θ = arctan((Xl - Xc) / R)

Substituting the values, we get:

θ = arctan((26.39 - 144.51) / 12) = -1.39 radians (approx)

So, the phase of the phasor current is -1.39 radians. This value is already within the range of -π to +π.