Fatty acid synthesis proceeds according to the following reaction:where n is a positive integer. Based on this, how many ADP and NADP+ molecules will be produced during synthesis of a 16-carbon fatty acid?A.7 ADP molecules and 14 NADP+ moleculesB.14 ADP molecules and 28 NADP+ moleculesC.8 ADP molecules and 15 NADP+ moleculesD.16 ADP molecules and 32 NADP+ molecules
Question
Fatty acid synthesis proceeds according to the following reaction:where n is a positive integer. Based on this, how many ADP and NADP+ molecules will be produced during synthesis of a 16-carbon fatty acid?A.7 ADP molecules and 14 NADP+ moleculesB.14 ADP molecules and 28 NADP+ moleculesC.8 ADP molecules and 15 NADP+ moleculesD.16 ADP molecules and 32 NADP+ molecules
Solution
The question seems to be missing the actual reaction, but generally, fatty acid synthesis involves the addition of two-carbon units. A 16-carbon fatty acid would therefore require 8 two-carbon units.
Each two-carbon unit added requires 1 ATP (which is converted to ADP) and 2 NADPH (which is converted to NADP+).
So, for a 16-carbon fatty acid:
- ATP -> ADP would occur 8 times (for 8 ADP molecules)
- NADPH -> NADP+ would occur 16 times (for 16 NADP+ molecules)
However, the first two-carbon unit does not require ATP, so we subtract one from the ADP count.
This gives us 7 ADP molecules and 16 NADP+ molecules.
However, this option is not listed in the choices provided. There may be a mistake in the question or the answer choices.
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