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Your section needs to elect muse and assistant muse. If there are 12 beautiful ladies in your room, in how many ways can students be chosen for these two positions?Group of answer choices132145156161

Question

Your section needs to elect muse and assistant muse. If there are 12 beautiful ladies in your room, in how many ways can students be chosen for these two positions?Group of answer choices132145156161

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Solution

The solution to this problem involves the use of permutations.

A permutation is an arrangement of objects in a specific order. The order of arrangement of the object is very crucial. The number of permutations on a set of n elements is given by n!.

In this case, we have 12 ladies and we want to choose 2 (a muse and an assistant muse). The order in which we choose the ladies matters here (because being a muse is different from being an assistant muse).

So, we use the formula for permutations of n items taken r at a time, which is:

P(n, r) = n! / (n-r)!

Here, n is the total number of items, and r is the number of items to choose.

So, P(12, 2) = 12! / (12-2)!

= 12*11 = 132

So, there are 132 ways to choose a muse and an assistant muse from 12 ladies.

This problem has been solved

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