Given a list (take from input), define a function searchAll, which returns the positions of the occurances of a given item (as a list)Test case 1:Enter elemnts: 1 2 3 1 1Enter element to search: 1[0, 3, 4]Sample Test CasesTest Case 1:Expected Output:Enter·elements:·1 2 3 1 1Enter·item·to·search:·1[0,·3,·4]Test Case 2:Expected Output:Enter·elements:·1 2 3 4Enter·item·to·search:·5[]

It seems like you're asking for a Python function that will return the indices of all occurrences of a specific item in a list. Here's how you can do it:

def searchAll(lst, item):
    return [i for i, x in enumerate(lst) if x == item]

# Test Case 1
lst = [1, 2, 3, 1, 1]
item = 1
print(searchAll(lst, item))  # Output: [0, 3, 4]

# Test Case 2
lst = [1, 2, 3, 4]
item = 5
print(searchAll(lst, item))  # Output: []

In this function, enumerate(lst) returns a tuple containing the index and value for each item in the list. The list comprehension [i for i, x in enumerate(lst) if x == item] generates a new list containing the index i for each occurrence of item in the list lst.

It seems like you want to create a function in Python that takes a list and an item as input, and returns the indices of all occurrences of the item in the list. Here's how you can do it:

def searchAll(lst, item):
    return [i for i, x in enumerate(lst) if x == item]

You can test this function with your test cases like this:

print(searchAll([1, 2, 3, 1, 1], 1))  # Output: [0, 3, 4]
print(searchAll([1, 2, 3, 4], 5))  # Output: []

In the searchAll function, enumerate(lst) returns a list of tuples where the first element of each tuple is the index and the second element is the value from the list. The list comprehension [i for i, x in enumerate(lst) if x == item] goes through each tuple, and if the value x is equal to the item we're looking for, it adds the index i to the output list.