Knowee
Questions
Features
Study Tools

There are 12 mangoes in a bag, out of which 4 are not ripe. If 5 mangoes are taken out of the bag randomly, what is the probability of selecting only ripen mangoes?

Question

There are 12 mangoes in a bag, out of which 4 are not ripe. If 5 mangoes are taken out of the bag randomly, what is the probability of selecting only ripen mangoes?

🧐 Not the exact question you are looking for?Go ask a question

Solution 1

Step 1: Identify the total number of mangoes. In this case, it's 12.

Step 2: Identify the number of ripe mangoes. Since 4 are not ripe, we subtract 4 from 12 to get 8 ripe mangoes.

Step 3: Identify the number of mangoes being selected. In this case, it's 5.

Step 4: Calculate the probability of selecting only ripe mangoes. This is done by dividing the number of ways to select 5 ripe mangoes from 8 by the total number of ways to select 5 mangoes from 12.

The number of ways to select 5 ripe mangoes from 8 is calculated using combinations, denoted as C(n, r) where n is the total number of items, and r is the number of items to choose. So, C(8, 5) = 8! / [(8-5)! * 5!] = 56.

The total number of ways to select 5 mangoes from 12 is calculated as C(12, 5) = 12! / [(12-5)! * 5!] = 792.

So, the probability of selecting only ripe mangoes is 56 / 792 = 0.0707 or approximately 7.07%.

This problem has been solved

Solution 2

Step 1: Identify the total number of mangoes. In this case, there are 12 mangoes.

Step 2: Identify the number of ripe mangoes. There are 12 total mangoes and 4 are not ripe, so there are 12 - 4 = 8 ripe mangoes.

Step 3: Identify the number of mangoes being selected. In this case, 5 mangoes are being selected.

Step 4: Calculate the probability of selecting only ripe mangoes. This is done by dividing the number of ways to select 5 ripe mangoes from 8 by the total number of ways to select 5 mangoes from 12.

The number of ways to select 5 ripe mangoes from 8 is calculated using combinations, which is denoted as C(n, r) where n is the total number of items, and r is the number of items to choose. So, the number of ways to select 5 ripe mangoes from 8 is C(8, 5).

Similarly, the total number of ways to select 5 mangoes from 12 is C(12, 5).

So, the probability of selecting only ripe mangoes is C(8, 5) / C(12, 5).

Step 5: Calculate the values of C(8, 5) and C(12, 5).

C(8, 5) = 8! / [5!(8-5)!] = 56 C(12, 5) = 12! / [5!(12-5)!] = 792

So, the probability of selecting only ripe mangoes is 56 / 792 = 0.0707 (rounded to four decimal places).

This problem has been solved

Solution 3

Sure, here's how you can calculate the probability:

Step 1: Identify the total number of mangoes. In this case, it's 12.

Step 2: Identify the number of ripe mangoes. Since 4 are not ripe, there are 12 - 4 = 8 ripe mangoes.

Step 3: We want to find the probability of picking 5 ripe mangoes.

Step 4: The number of ways to pick 5 mangoes out of 8 ripe ones can be calculated using combinations. This is denoted as C(8,5).

Step 5: Similarly, the total number of ways to pick 5 mangoes out of 12 is C(12,5).

Step 6: The probability of picking 5 ripe mangoes is therefore C(8,5) / C(12,5).

Step 7: Calculate C(8,5) and C(12,5).

C(n, r) = n! / [r!(n-r)!]

So, C(8,5) = 8! / [5!(8-5)!] = 56 And, C(12,5) = 12! / [5!(12-5)!] = 792

Step 8: Substitute these values back into the probability formula to get the final answer.

Probability = C(8,5) / C(12,5) = 56 / 792 = 0.0707

So, the probability of selecting only ripe mangoes is approximately 0.0707 or 7.07%.

This problem has been solved

Solution 4

Step 1: Identify the total number of mangoes. In this case, it's 12.

Step 2: Identify the number of ripe mangoes. Since 4 are not ripe, we subtract 4 from 12 to get 8 ripe mangoes.

Step 3: Identify the number of mangoes being selected. In this case, it's 5.

Step 4: We need to find the probability of selecting 5 ripe mangoes. This is a combination problem, as the order of selection does not matter.

Step 5: The formula for combination is C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

Step 6: Calculate the total number of ways to select 5 mangoes from 12. Using the combination formula, C(12, 5) = 12! / [5!(12-5)!] = 792.

Step 7: Calculate the number of ways to select 5 ripe mangoes from 8. Using the combination formula, C(8, 5) = 8! / [5!(8-5)!] = 56.

Step 8: The probability of selecting 5 ripe mangoes is the number of ways to select 5 ripe mangoes divided by the total number of ways to select 5 mangoes. So, the probability = 56 / 792 = 0.0707.

So, the probability of selecting only ripe mangoes is approximately 0.0707 or 7.07%.

This problem has been solved

Solution 5

Step 1: Identify the total number of mangoes. In this case, it's 12.

Step 2: Identify the number of ripe mangoes. Since 4 are not ripe, we subtract 4 from 12 to get 8 ripe mangoes.

Step 3: Identify the number of mangoes being selected. In this case, it's 5.

Step 4: Calculate the probability of selecting only ripe mangoes. This is done by dividing the number of ways to choose 5 ripe mangoes from 8 by the total number of ways to choose 5 mangoes from 12.

The number of ways to choose 5 ripe mangoes from 8 is calculated using the combination formula, which is C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and ! denotes factorial.

So, the number of ways to choose 5 ripe mangoes from 8 is C(8, 5) = 8! / [5!(8-5)!] = 56.

Similarly, the total number of ways to choose 5 mangoes from 12 is C(12, 5) = 12! / [5!(12-5)!] = 792.

So, the probability of selecting only ripe mangoes is 56 / 792 = 0.0707 or 7.07% when rounded to two decimal places.

This problem has been solved

Solution 6

Step 1: Identify the total number of mangoes. In this case, it's 12.

Step 2: Identify the number of ripe mangoes. Since 4 are not ripe, we subtract 4 from 12 to get 8 ripe mangoes.

Step 3: Identify the number of mangoes being selected. In this case, it's 5.

Step 4: We need to find the probability of selecting 5 ripe mangoes. This is a combination problem, as the order of selection does not matter.

Step 5: The formula for combination is C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

Step 6: Calculate the total number of ways to select 5 mangoes from 12. Using the combination formula, C(12, 5) = 12! / [5!(12-5)!] = 792.

Step 7: Calculate the number of ways to select 5 ripe mangoes from 8. Using the combination formula, C(8, 5) = 8! / [5!(8-5)!] = 56.

Step 8: The probability of selecting 5 ripe mangoes is the number of ways to select 5 ripe mangoes divided by the total number of ways to select 5 mangoes. So, the probability = 56 / 792 = 0.0707.

So, the probability of selecting only ripe mangoes when picking 5 out of the bag is approximately 0.0707 or 7.07%.

This problem has been solved

Similar Questions

A fruit basket contains 6 apples, x mangoes, x + 3 guavas. If a fruit is chosen randomly from the basket, then the probability of it being guava is 37 . What is the probability of choosing two fruits from the basket one after the other without replacement, such that the first fruit chosen is a mango and the second fruit chosen is an apple?

In how many ways is it possible to make a selection by taking any number of 15 fruits, namely 3 oranges, 5 apples and 7 mangoes?

Cameron has a bag that contains strawberry chews, apple chews, and watermelon chews. He performs an experiment. Cameron randomly removes a chew from the bag, records the result, and returns the chew to the bag. Cameron performs the experiment 40 times. The results are shown below:A strawberry chew was selected 21 times.A apple chew was selected 7 times.A watermelon chew was selected 12 times.Based on these results, express the probability that the next chew Cameron removes from the bag will be a flavor other than watermelon as a fraction in simplest form.

In a bag, there are 8 red, 10 blue and 12 green balls. A ball is picked randomly from the bag and 5 blue balls are added to the bag. Now, one ball is picked randomly from the bag. What is the probability that the first ball picked is red and the second ball picked is blue?

There are 10 balls in a bag numbered from 1 to 10. Seven balls are selected at random. How many different ways are there of selecting the seven balls?

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.