Knowee
Questions
Features
Study Tools

For some integer m, every even integer is of the form

Question

For some integer m, every even integer is of the form

🧐 Not the exact question you are looking for?Go ask a question

Solution

To prove that every even integer is of the form "m", we can follow these steps:

Step 1: Let's consider an arbitrary even integer "n".

Step 2: By definition, an even integer can be expressed as "n = 2k", where "k" is an integer.

Step 3: Now, let's define "m" as "m = k".

Step 4: Substituting "k" in the expression for "n", we have "n = 2m".

Step 5: Therefore, we have shown that every even integer "n" can be expressed in the form "m", where "m" is an integer.

Step 6: Since we have proven this for an arbitrary even integer, we can conclude that every even integer is of the form "m".

Thus, we have successfully demonstrated that every even integer is of the form "m".

This problem has been solved

Similar Questions

For some integer q, every odd integer is of the form

If m and n are odd positive integers, then m2 + n2 is even, but not divisible by 4. Justify.

An even number can be expressed as the square of an integer as well as a cube of another integer. Then the number has to be necessarily divisible by:

For some integer n, the odd integer is represented in the form of:

For some integer p, every even integer is of the formDeselect Answer p 2p + 1 2p p + 1

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.