Knowee
Questions
Features
Study Tools

Solve the following: 1.    (siny – y sinx) dx + (cosx + xcosy – y ) dy = 0 2.    ( yex – 2x ) dx + ex dy = 0 3.    (2x siny + y) dx + (x2 cosy + x ) dy = 0 4.    (2x3 – y) dx + x dy = 0

Question

Solve the following: 1.    (siny – y sinx) dx + (cosx + xcosy – y ) dy = 0 2.    ( yex – 2x ) dx + ex dy = 0 3.    (2x siny + y) dx + (x2 cosy + x ) dy = 0 4.    (2x3 – y) dx + x dy = 0

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve the given differential equations step by step:

  1. (siny – y sinx) dx + (cosx + xcosy – y ) dy = 0: Rearrange the equation to isolate dy/dx: (siny – y sinx) dx = (y - cosx - xcosy) dy Divide both sides by (y - cosx - xcosy): (siny – y sinx)/(y - cosx - xcosy) dx = dy Integrate both sides with respect to x: ∫(siny – y sinx)/(y - cosx - xcosy) dx = ∫dy Solve the integral on the left side to find the solution.

  2. (yex – 2x) dx + ex dy = 0: Rearrange the equation to isolate dy/dx: (yex – 2x) dx = -ex dy Divide both sides by -ex: (yex – 2x)/ex dx = dy Integrate both sides with respect to x: ∫(yex – 2x)/ex dx = ∫dy Solve the integral on the left side to find the solution.

  3. (2x siny + y) dx + (x2 cosy + x ) dy = 0: Rearrange the equation to isolate dy/dx: (2x siny + y) dx = -(x2 cosy + x) dy Divide both sides by -(x2 cosy + x): (2x siny + y)/-(x2 cosy + x) dx = dy Integrate both sides with respect to x: ∫(2x siny + y)/-(x2 cosy + x) dx = ∫dy Solve the integral on the left side to find the solution.

  4. (2x3 – y) dx + x dy = 0: Rearrange the equation to isolate dy/dx: (2x3 – y) dx = -x dy Divide both sides by -x: (2x3 – y)/-x dx = dy Integrate both sides with respect to x: ∫(2x3 – y)/-x dx = ∫dy Solve the integral on the left side to find the solution.

Please note that the specific solutions to these differential equations will depend on the integration results, which can vary depending on the complexity of the integrals involved.

This problem has been solved

Similar Questions

vii) cos x dydx − y sin x + y2 = 0

Q 60. Find dy/dx, given y = (2tanx * sin2x) / (sec'x - 1) ? Ops: A. •-8cosxsinx B. 0-8cos-x C. © -4cosxsinx D. 0-8cos2x.sin2

Find the general solution of the following differential equations.(a) ysinxdx + (y3 - 2y2 cosx + cosx)dy = 0

The solutions of the differential equation dydx=siny+xsin2y−xcosy is

solve d^2y /d^2x - 4 dy/dx+y= cosx cos2x

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.