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Geometry & Magnetic nature of [PtCl4]2– & [PdCl4]2– are:-Both square planar and diamagneticBoth square planar and paramagneticBoth tetrahedral and diamagneticNone of these

Question

Geometry & Magnetic nature of [PtCl4]2– & [PdCl4]2– are:-Both square planar and diamagneticBoth square planar and paramagneticBoth tetrahedral and diamagneticNone of these

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Solution

The geometry and magnetic nature of [PtCl4]2– and [PdCl4]2– are both square planar and diamagnetic.

Here's why:

  1. [PtCl4]2–: Platinum (Pt) in [PtCl4]2– has an oxidation state of +2. The electronic configuration of Pt is [Xe] 4f14 5d9 6s1. When it loses two electrons, it becomes [Xe] 4f14 5d7 6s0. The 5d7 electrons will pair up, leaving no unpaired electrons. This makes it diamagnetic. The complex forms a square planar geometry due to dsp2 hybridization.

  2. [PdCl4]2–: Palladium (Pd) in [PdCl4]2– also has an oxidation state of +2. The electronic configuration of Pd is [Kr] 4d10 5s0. When it loses two electrons, it becomes [Kr] 4d8. The 4d8 electrons will pair up, leaving no unpaired electrons. This makes it also diamagnetic. The complex forms a square planar geometry due to dsp2 hybridization.

Therefore, both [PtCl4]2– and [PdCl4]2– are square planar and diamagnetic.

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