n a different experiment it is observed that 252 J of heat must be absorbed to raise the temperature of 50.0 g of Ni(s) from 20.0 °C to 31.4 °C. Calculate the specific heat of Ni in both J/g·°C and cal/g·°C.
Question
n a different experiment it is observed that 252 J of heat must be absorbed to raise the temperature of 50.0 g of Ni(s) from 20.0 °C to 31.4 °C. Calculate the specific heat of Ni in both J/g·°C and cal/g·°C.
Solution
The specific heat capacity (c) of a substance can be calculated using the formula:
q = mcΔT
where: q = heat energy absorbed or released (in joules, J) m = mass of the substance (in grams, g) ΔT = change in temperature (in Celsius, °C)
In this case, we know that: q = 252 J m = 50.0 g ΔT = 31.4°C - 20.0°C = 11.4°C
We can rearrange the formula to solve for c:
c = q / (mΔT)
Substituting the known values:
c = 252 J / (50.0 g * 11.4°C) = 0.442 J/g·°C
This is the specific heat capacity in J/g·°C.
To convert this to cal/g·°C, we use the conversion factor 1 cal = 4.184 J:
c = 0.442 J/g·°C * (1 cal / 4.184 J) = 0.106 cal/g·°C
So, the specific heat capacity of Ni is 0.442 J/g·°C or 0.106 cal/g·°C.
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