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Find the linearization of the function f(x) = x + 1 at a = 8 and use it to approximate the numbers 8.95 and 9.04. Are these approximations overestimates or underestimates?SolutionThe derivative of f(x) = (x + 1)1⁄2 isf ′(x) = 12​(x+1)−(12​) ,and so we have f(8) = and f ′(8) = . Putting these values into the equation L(x) = f(a) + f ′(a)(x − a), we see that the linearization isL(x)= f(8) + f '(8)(x − 8) = +  (x − 8)= .The corresponding linear approximation isx + 1 ≈ + x6        (when x is near 8).In particular, we have8.95 ≈ 53 + 6 =     (round to four decimal places)and  9.04 ≈ 53 + 6 =     (round to four decimal places).

Question

Find the linearization of the function f(x) = x + 1 at a = 8 and use it to approximate the numbers 8.95 and 9.04. Are these approximations overestimates or underestimates?SolutionThe derivative of f(x) = (x + 1)1⁄2 isf ′(x) = 12​(x+1)−(12​) ,and so we have f(8) = and f ′(8) = . Putting these values into the equation L(x) = f(a) + f ′(a)(x − a), we see that the linearization isL(x)= f(8) + f '(8)(x − 8) = +  (x − 8)= .The corresponding linear approximation isx + 1 ≈ + x6        (when x is near 8).In particular, we have8.95 ≈ 53 + 6 =     (round to four decimal places)and  9.04 ≈ 53 + 6 =     (round to four decimal places).

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Solution

The function given is f(x) = x + 1. The linearization of a function at a point a is given by the equation L(x) = f(a) + f'(a)(x - a), where f'(a) is the derivative of the function at the point a.

Step 1: Find the derivative of the function f(x) = x + 1. The derivative is f'(x) = 1.

Step 2: Substitute a = 8 into the function and its derivative to get f(8) = 8 + 1 = 9 and f'(8) = 1.

Step 3: Substitute these values into the linearization equation to get L(x) = 9 + 1(x - 8) = x + 1.

Step 4: Use this linear approximation to estimate the values of the function at x = 8.95 and x = 9.04. We get L(8.95) = 8.95 + 1 = 9.95 and L(9.04) = 9.04 + 1 = 10.04.

Step 5: Compare these approximations to the actual values of the function at these points. The actual values are f(8.95) = 8.95 + 1 = 9.95 and f(9.04) = 9.04 + 1 = 10.04.

Since the approximations are equal to the actual values, they are neither overestimates nor underestimates.

This problem has been solved

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