Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula of the compound formed in the space provided.element #1 element #2 Forms ionic compound? empirical formula of ionic compoundsodium bromine yesnocalcium sodium yesnooxygen strontium yesnopotassium chlorine yesno
Question
Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula of the compound formed in the space provided.element #1 element #2 Forms ionic compound? empirical formula of ionic compoundsodium bromine yesnocalcium sodium yesnooxygen strontium yesnopotassium chlorine yesno
Solution
I'm sorry, but you didn't provide a specific question or a table. However, I can tell you generally how to determine if two elements will form an ionic compound and how to write the empirical formula.
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Sodium (Na) and Bromine (Br): Sodium is a metal and bromine is a non-metal. Metals and non-metals usually form ionic compounds. The empirical formula would be NaBr.
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Calcium (Ca) and Sodium (Na): Both are metals, so they would not typically form an ionic compound.
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Oxygen (O) and Strontium (Sr): Oxygen is a non-metal and strontium is a metal. They would form an ionic compound. The empirical formula would be SrO.
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Potassium (K) and Chlorine (Cl): Potassium is a metal and chlorine is a non-metal. They would form an ionic compound. The empirical formula would be KCl.
Please provide a specific question or a table for a more accurate answer.
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To fill in the table, we need to balance the charges of the cations and anions to find the empirical formula for each ionic compound. Then we can name the compound accordingly. 1. For the cation Fe^3+ and the anion S^2-: - To balance the charges, we need two Fe^3+ ions for every three S^2- ions. - The empirical formula is Fe2S3. - The name of the compound is iron(III) sulfide. 2. For the cation Pb^4+ and the anion O^2-: - To balance the charges, we need two Pb^4+ ions for every four O^2- ions (which simplifies to one Pb^4+ for every two O^2-). - The empirical formula is PbO2. - The name of the compound is lead(IV) oxide. 3. For the cation Mn^2+ and the anion N^3-: - To balance the charges, we need three Mn^2+ ions for every two N^3- ions. - The empirical formula is Mn3N2. - The name of the compound is manganese(II) nitride. 4. For the cation Fe^2+ and the anion P^3-: - To balance the charges, we need three Fe^2+ ions for every two P^3- ions. - The empirical formula is Fe3P2. - The name of the compound is iron(II) phosphide. So the completed table should list the empirical formulas and names of the compounds as follows: - Fe2S3, iron(III) sulfide- PbO2, lead(IV) oxide- Mn3N2, manganese(II) nitride- Fe3P2, iron(II) phosphide
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