What is the area of a rectangle with vertices at (7, 3), (12, 3), (12, 11), and (7, 11)?A.45 units2B.26 units2C.20 units2D.40 units2
Question
What is the area of a rectangle with vertices at (7, 3), (12, 3), (12, 11), and (7, 11)?A.45 units2B.26 units2C.20 units2D.40 units2
Solution
The area of a rectangle is calculated by multiplying its length by its width.
The length of the rectangle can be determined by the difference in the x-coordinates of its vertices. In this case, it's (12-7) = 5 units.
The width of the rectangle can be determined by the difference in the y-coordinates of its vertices. In this case, it's (11-3) = 8 units.
Therefore, the area of the rectangle is (length * width) = (5 units * 8 units) = 40 units^2.
So, the correct answer is D.40 units^2.
Similar Questions
Calculate the area of the rectangle with the coordinates 𝐴=(3,7), 𝐵=(12,7), 𝐶=(12,4), and 𝐷=(3,4).HINT: The formula for the area of a rectangle is length × width.32 units squared18 units squared27 units squared30 units squared
What is area (in sq units) of a triangle with sides 10, 10 and 12?
Calculate the area of the rectangle shown.HINT: The formula for the area of a rectangle is length × width.View Image Description18 units squared20 units squared12 units squared15 units squared
Part A: The area of a square is (9x2 − 12x + 4) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work. (5 points)Part B: The area of a rectangle is (25x2 − 16y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work. (5 points)
The area of the parallelogram with vertices at the origin, (7, 2), (5, 9) and (12,11) isQuestion 1Answera.53 square unitsb.35 square unitsc.50 square unitsd.25.5 square units
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.