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what is the result of the following:123A = torch.tensor([[0, 1, 1], [1, 0, 1]])B = torch.tensor([[1, 1], [1, 1], [-1, 1]])A_times_B = torch.mm(A,B)1 pointtensor([[0, 2], [0, 2]])tensor([[0, 1], [1, 4]])

Question

what is the result of the following:123A = torch.tensor([[0, 1, 1], [1, 0, 1]])B = torch.tensor([[1, 1], [1, 1], [-1, 1]])A_times_B = torch.mm(A,B)1 pointtensor([[0, 2], [0, 2]])tensor([[0, 1], [1, 4]])

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Solution

The result of the multiplication of tensors A and B (A_times_B) is a new tensor. The multiplication is done using the torch.mm function, which performs a matrix multiplication of the two tensors.

Here are the tensors:

A = torch.tensor([[0, 1, 1], [1, 0, 1]]) B = torch.tensor([[1, 1], [1, 1], [-1, 1]])

The multiplication is done as follows:

First row of A_times_B: (01 + 11 + 1*-1 , 01 + 11 + 1*1) = (0, 2)

Second row of A_times_B: (11 + 01 + 1*-1 , 11 + 01 + 1*1) = (0, 2)

So, A_times_B = torch.tensor([[0, 2], [0, 2]])

Therefore, the correct answer is tensor([[0, 2], [0, 2]]).

This problem has been solved

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