(p → q) ∧ (p → r) is logically equivalent top ∧ (q ∨ r)p → (q ∧ r) p ∨ (q ∧ r) p → (q ∨ r)
Question
(p → q) ∧ (p → r) is logically equivalent top ∧ (q ∨ r)p → (q ∧ r) p ∨ (q ∧ r) p → (q ∨ r)
Solution
The statement seems to be a mix of different logical expressions, and it's a bit unclear. However, I'll try to break down the logical equivalences as best as I can.
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(p → q) ∧ (p → r): This means "if p then q" and "if p then r". In other words, p implies both q and r.
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p ∧ (q ∨ r): This means "p and (either q or r)". In other words, p must be true, and either q or r (or both) must be true.
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p → (q ∧ r): This means "if p then (both q and r)". In other words, if p is true, then both q and r must be true.
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p ∨ (q ∧ r): This means "either p or (both q and r)". In other words, either p is true, or both q and r are true.
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p → (q ∨ r): This means "if p then (either q or r)". In other words, if p is true, then either q or r (or both) must be true.
The original statement seems to be a mix of these different expressions, and without further context or clarification, it's difficult to determine the exact logical equivalence. However, I hope this breakdown helps clarify the individual components of the statement.
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