In humans, the sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous for the sickle-cell allele. A man and woman each carry the trait, but do not have sickle-cell disease. What is the probability that their first two children will both have sickle-cell disease?Multiple Choice1/23/81/41/81/16
Question
In humans, the sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous for the sickle-cell allele. A man and woman each carry the trait, but do not have sickle-cell disease. What is the probability that their first two children will both have sickle-cell disease?Multiple Choice1/23/81/41/81/16
Solution
The probability of two parents who are carriers of the sickle-cell trait (heterozygous) having a child with sickle-cell disease (homozygous) is 1/4. This is because there are four possible combinations of the two alleles each parent can pass on: AA, Aa, aA, and aa. Only the "aa" combination results in sickle-cell disease.
To find the probability that their first two children will both have sickle-cell disease, you multiply the individual probabilities together. So, (1/4) * (1/4) = 1/16.
So, the answer is 1/16.
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