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A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:    [2019]A: The mass is at the highest pointB: The wire is horizontalC: The mass is at the lowest pointD: Inclined at an angle of 60° from vertical

Question

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:    [2019]A: The mass is at the highest pointB: The wire is horizontalC: The mass is at the lowest pointD: Inclined at an angle of 60° from vertical

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Solution

The wire is most likely to break when the mass is at the lowest point (Option C).

Here's why:

When the mass is whirled in a vertical circle, it experiences two forces: gravitational force (mg) and the tension in the wire.

At the highest point of the circle, the tension and gravitational force both act downwards, so the total force is the sum of these two forces.

At the lowest point of the circle, the tension acts upwards and the gravitational force acts downwards. The tension must be greater than the gravitational force to keep the mass moving in a circle. Therefore, the tension is at its maximum at the lowest point of the circle, making this the point where the wire is most likely to break.

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