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How far would a freely-falling object fall from a position of rest in 6 sec.

Question

How far would a freely-falling object fall from a position of rest in 6 sec.

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Solution

To calculate the distance an object falls freely from rest, we can use the equation of motion:

d = 0.5 * g * t^2

where:

  • d is the distance,
  • g is the acceleration due to gravity (approximated as 9.8 m/s^2 on Earth), and
  • t is the time.

Given that the time t is 6 seconds, we can substitute the values into the equation:

d = 0.5 * 9.8 * (6^2)

Solving this equation will give us the distance the object falls in 6 seconds.

Let's calculate:

d = 0.5 * 9.8 * 36 d = 176.4 meters

So, a freely-falling object would fall approximately 176.4 meters from a position of rest in 6 seconds.

This problem has been solved

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