How far would a freely-falling object fall from a position of rest in 6 sec.
Question
How far would a freely-falling object fall from a position of rest in 6 sec.
Solution
To calculate the distance an object falls freely from rest, we can use the equation of motion:
d = 0.5 * g * t^2
where:
- d is the distance,
- g is the acceleration due to gravity (approximated as 9.8 m/s^2 on Earth), and
- t is the time.
Given that the time t is 6 seconds, we can substitute the values into the equation:
d = 0.5 * 9.8 * (6^2)
Solving this equation will give us the distance the object falls in 6 seconds.
Let's calculate:
d = 0.5 * 9.8 * 36 d = 176.4 meters
So, a freely-falling object would fall approximately 176.4 meters from a position of rest in 6 seconds.
Similar Questions
How long does it take a falling object (dropped from rest) to reach a downward velocity of 113 m/s?
What is the velocity of an object accelerating at 5.0m/s 2 after 6.0s having started from rest?
An object is released from rest at t = 0 at the top of a cliff.How far does it fall during the second second of its fall (i.e., from t = 1 s to t = 2 s)?Neglect friction and express your answer in meters.
An object is released from rest at t = 0. How far does it fall during the first second after release?Neglect air friction and express your answer in meters.
A ball thrown up vertically returns to the thrower after 6 s. (a) the velocity with which it was thrown up. (b) the maximum height it reaches, and (c) its position after 4 s.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.