Fill in the blank in the function below so that the function prints the integers from 0 up to the integer value it was given for N. That is, if the function is executed with the value of N being 6, it should print 0, 1, 2, 3, 4, 5, 6.def print_integer(N): if (_________): print_integer(N - 1) print(N)
Question
Fill in the blank in the function below so that the function prints the integers from 0 up to the integer value it was given for N. That is, if the function is executed with the value of N being 6, it should print 0, 1, 2, 3, 4, 5, 6.def print_integer(N): if (_________): print_integer(N - 1) print(N)
Solution
The blank in the function should be filled with "N >= 0". This condition checks if N is greater than or equal to 0. If it is, the function calls itself with the argument N - 1, and then prints N. This results in the numbers from 0 to N being printed in ascending order. Here is the completed function:
def print_integer(N):
if (N >= 0):
print_integer(N - 1)
print(N)
This function uses recursion to print the numbers. The base case for the recursion is when N is less than 0, at which point the function stops calling itself.
Similar Questions
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