To solve this problem, we need to use the concept of centripetal force. When the driver feels 'weightless', the normal force acting on the driver is zero. This means that the gravitational force is providing the necessary centripetal force for the car to stay in circular motion.

The formula for centripetal force is F = mv^2/r, where m is the mass, v is the velocity, and r is the radius of curvature. In this case, the centripetal force is equal to the gravitational force, so we have mg = mv^2/r.

We can cancel out the mass on both sides, and we're left with g = v^2/r. We want to solve for r, so we rearrange the equation to get r = v^2/g.

The velocity is given as 60.0 km/h, but we need to convert this to m/s by multiplying by 1000 (to convert km to m) and dividing by 3600 (to convert hours to seconds). This gives us v = 60.0 * 1000 / 3600 = 16.67 m/s.

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting these values into the equation gives us r = (16.67 m/s)^2 / 9.8 m/s^2 = 28.35 m.

So, the radius of curvature of the second speed hump is approximately 28.35 m.

Question

To solve this problem, we need to use the concept of centripetal force. When the driver feels 'weightless', the normal force acting on the driver is zero. This means that the gravitational force is providing the necessary centripetal force for the car to stay in circular motion.

The formula for centripetal force is F = mv^2/r, where m is the mass, v is the velocity, and r is the radius of curvature. In this case, the centripetal force is equal to the gravitational force, so we have mg = mv^2/r.

We can cancel out the mass on both sides, and we're left with g = v^2/r. We want to solve for r, so we rearrange the equation to get r = v^2/g.

The velocity is given as 60.0 km/h, but we need to convert this to m/s by multiplying by 1000 (to convert km to m) and dividing by 3600 (to convert hours to seconds). This gives us v = 60.0 * 1000 / 3600 = 16.67 m/s.

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting these values into the equation gives us r = (16.67 m/s)^2 / 9.8 m/s^2 = 28.35 m.

So, the radius of curvature of the second speed hump is approximately 28.35 m.

Knowee AI · Accepted Answer

To solve this problem, we need to use the concept of centripetal force. When the driver feels 'weightless', the normal force acting on the driver is zero. This means that the gravitational force is providing the necessary centripetal force for the car to stay in circular motion.

The formula for centripetal force is F = mv^2/r, where m is the mass, v is the velocity, and r is the radius of curvature. In this case, the centripetal force is equal to the gravitational force, so we have mg = mv^2/r.

We can cancel out the mass on both sides, and we're left with g = v^2/r. We want to solve for r, so we rearrange the equation to get r = v^2/g.

The velocity is given as 60.0 km/h, but we need to convert this to m/s by multiplying by 1000 (to convert km to m) and dividing by 3600 (to convert hours to seconds). This gives us v = 60.0 * 1000 / 3600 = 16.67 m/s.

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting these values into the equation gives us r = (16.67 m/s)^2 / 9.8 m/s^2 = 28.35 m.

So, the radius of curvature of the second speed hump is approximately 28.35 m.

Question 8(2 marks)The car continues along the road, now travelling at 60.0 km h-1. There is another speed hump. As the car travels over this speed hump, the driver just starts to feel ‘weightless’. Calculate the radius of curvature of this second speed hump.

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