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If 2200 - 2192.31 + 2n is a perfect square then n =

Question

If 2200 - 2192.31 + 2n is a perfect square then n =

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Solution

The given expression is 2200 - 2192.31 + 2n.

First, simplify the constants: 2200 - 2192.31 = 7.69.

So, the expression becomes 7.69 + 2n.

For this to be a perfect square, n must be such that 7.69 + 2n is the square of an integer.

Let's denote the integer whose square we're looking for as m, so m^2 = 7.69 + 2n.

We can rearrange this equation to solve for n: 2n = m^2 - 7.69.

Finally, divide by 2 to isolate n: n = (m^2 - 7.69) / 2.

So, n will be equal to (m^2 - 7.69) / 2 for some integer m such that m^2 > 7.69.

The smallest perfect square greater than 7.69 is 9, which is 3^2.

So, if m = 3, then n = (9 - 7.69) / 2 = 0.655.

Therefore, n = 0.655 if 7.69 + 2n is a perfect square.

This problem has been solved

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