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. H2O2 changes Cr2O72- ion to CrO5 in an acidic medium, the oxidation state of Cr in CrO5 is(a) +6(b) +5(c) -10(d) +3Answer: (a)

Question

. H2O2 changes Cr2O72- ion to CrO5 in an acidic medium, the oxidation state of Cr in CrO5 is(a) +6(b) +5(c) -10(d) +3Answer: (a)

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Solution

The oxidation state of Cr in CrO5 is +6.

Here's how you can determine this:

  1. Oxygen usually has an oxidation state of -2.

  2. In CrO5, there are five oxygen atoms, so the total oxidation state for all oxygen atoms is -2 * 5 = -10.

  3. The sum of the oxidation states in a neutral compound is zero.

  4. Therefore, the oxidation state of Cr in CrO5 is +6 because +6 + (-10) = 0.

So, the correct answer is (a) +6.

This problem has been solved

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