10 Magnesium carbonate decomposes when heated in a Bunsen burner flame.Values for the standard enthalpies of formation, , of the species involved are shown.MgCO 3 = –1095.8 kJ mol –1MgO = –601.7 kJ mol –1CO 2 = –393.5 kJ mol –1What is the standard enthalpy change for the decomposition of magnesium carbonate?A +100.6 kJ mol –1B +887.6 kJ mol –1C +1095.8 kJ mol –1D +2091 kJ mol –
Question
10 Magnesium carbonate decomposes when heated in a Bunsen burner flame.Values for the standard enthalpies of formation, , of the species involved are shown.MgCO 3 = –1095.8 kJ mol –1MgO = –601.7 kJ mol –1CO 2 = –393.5 kJ mol –1What is the standard enthalpy change for the decomposition of magnesium carbonate?A +100.6 kJ mol –1B +887.6 kJ mol –1C +1095.8 kJ mol –1D +2091 kJ mol –
Solution
The standard enthalpy change for a reaction can be calculated using Hess's Law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for each step in the reaction, regardless of the path taken.
The decomposition of magnesium carbonate can be represented by the following equation:
MgCO3(s) → MgO(s) + CO2(g)
The standard enthalpy change for this reaction (ΔH°) can be calculated using the standard enthalpies of formation (ΔHf°) of the reactants and products:
ΔH° = [Σ ΔHf°(products)] - [Σ ΔHf°(reactants)]
For the products, we have one mole of MgO and one mole of CO2. For the reactant, we have one mole of MgCO3. Substituting the given values into the equation gives:
ΔH° = [(1 mol)(-601.7 kJ/mol) + (1 mol)(-393.5 kJ/mol)] - [(1 mol)(-1095.8 kJ/mol)] = [-601.7 kJ - 393.5 kJ] - [-1095.8 kJ] = [-995.2 kJ] - [-1095.8 kJ] = 100.6 kJ
Therefore, the standard enthalpy change for the decomposition of magnesium carbonate is +100.6 kJ/mol, which corresponds to option A.
Similar Questions
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