A stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?
Question
A stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?
Solution
To initialize an empty stack with capacity N for the above implementation, you would need to set the variable 'pos' to N. This is because the 'push' operation decreases the 'pos' value and the 'pop' operation increases it. So, to start with an empty stack, 'pos' should be at its maximum value, which is N. Here is the code:
pos ← N
This means that the stack is empty and ready to be filled up to its capacity, N. The first element will be inserted at position N-1 (since 'pos' is decremented in the 'push' operation), and the last element will be inserted at position 0.
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