Context: A uniform magnetic field exists in a region given by A rod of length 5 m placed along y - axis is moved along x - axis with a constant speed Then induced EMF in the rod will be A uniform magnetic field exists in a region given by B=3i + 4j + 5k T A rod of length 5 m placed along y - axis is moved along x - axis with a constant speed 1ms^-1 Then induced EMF in the rod will be ?
Question
Context: A uniform magnetic field exists in a region given by A rod of length 5 m placed along y - axis is moved along x - axis with a constant speed Then induced EMF in the rod will be
A uniform magnetic field exists in a region given by B=3i + 4j + 5k T A rod of length 5 m placed along y - axis is moved along x - axis with a constant speed 1ms^-1 Then induced EMF in the rod will be ?
Solution
The induced EMF in a rod moving in a magnetic field can be calculated using Faraday's law of electromagnetic induction, which states that the induced EMF is equal to the rate of change of magnetic flux.
However, in this case, since the rod is moving perpendicular to its length and the magnetic field, the induced EMF (E) can be calculated using the formula:
E = B * L * v
where: B is the magnetic field strength, L is the length of the rod, and v is the velocity of the rod.
Given that the rod is moving along the x-axis, the component of the magnetic field that will contribute to the induced EMF is the one along the y-axis. Therefore, B in the formula will be the y-component of the magnetic field, which is 4 T.
Substituting the given values into the formula, we get:
E = 4 T * 5 m * 1 m/s = 20 V
Therefore, the induced EMF in the rod will be 20 volts.
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