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The ratio of Ethan to Noah's savings was 3 : 7 at first. After Ethan saved another $121 and Noah saved another $44, Ethan had twice of Noah. How much did Ethan have in the end?

Question

The ratio of Ethan to Noah's savings was 3 : 7 at first. After Ethan saved another 121andNoahsavedanother121 and Noah saved another 44, Ethan had twice of Noah. How much did Ethan have in the end?

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Solution

Let's solve this step by step:

Step 1: Let's assume the initial savings of Ethan and Noah are 3x and 7x respectively.

Step 2: According to the problem, after Ethan saved another 121andNoahsavedanother121 and Noah saved another 44, Ethan had twice of Noah. So, we can write this as an equation: 3x + 121 = 2(7x + 44).

Step 3: Simplify the equation: 3x + 121 = 14x + 88.

Step 4: Rearrange the equation to find the value of x: 14x - 3x = 121 - 88, which simplifies to 11x = 33, so x = 3.

Step 5: Substitute x = 3 back into the equation for Ethan's savings: 3x + 121 = 3*3 + 121 = 9 + 121 = $130.

So, Ethan had $130 in the end.

This problem has been solved

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