2z−4≤−3z+62𝑧−4≤−3𝑧+6Step 2 of 2: Graph the solution to the given inequality.

Apologies for the confusion, but it seems like the question you want to be answered is not fully provided. However, I can help you solve and graph the inequality "2z - 4 ≤ -3z + 6". Here are the steps:

Step 1: Solve the inequality First, we need to get all the z terms on one side of the inequality and the constants on the other side.

2z + 3z ≤ 6 + 4

This simplifies to:

5z ≤ 10

Then, divide each side by 5 to solve for z:

z ≤ 2

Step 2: Graph the solution To graph this solution on a number line:

1. Draw a number line and mark the point that corresponds to 2.
2. Since the inequality is "less than or equal to", we fill in the point at 2 to indicate that it is included in the solution.
3. Draw a line extending to the left from the point at 2, towards negative infinity, to show that all numbers less than 2 are also solutions.

And that's it! The graph of the solution to the inequality "2z - 4 ≤ -3z + 6" is a filled-in point at 2 with a line extending to the left.