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๐‘Šโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘กโ„Ž๐‘’ย ๐‘š๐‘Ž๐‘ฅ๐‘–๐‘š๐‘ข๐‘šย ๐‘๐‘œ๐‘ ๐‘ ๐‘–๐‘๐‘™๐‘’ย ๐‘Ÿ๐‘Ž๐‘›๐‘˜ย ๐‘œ๐‘“ย ๐‘Ž๐‘›ย ๐‘šย ร—ย ๐‘›ย ๐‘š๐‘Ž๐‘ก๐‘Ÿ๐‘–๐‘ฅย ๐ดย ๐‘กโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘›๐‘œ๐‘กย ๐‘ ๐‘ž๐‘ข๐‘Ž๐‘Ÿ๐‘’?ย Question 10Select one:ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย =ย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย โ‰คย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)ย ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย =ย ๐‘š๐‘Ž๐‘ฅ(๐‘š,ย ๐‘›)๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย โ‰ฅย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)

Question

๐‘Šโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘กโ„Ž๐‘’ย ๐‘š๐‘Ž๐‘ฅ๐‘–๐‘š๐‘ข๐‘šย ๐‘๐‘œ๐‘ ๐‘ ๐‘–๐‘๐‘™๐‘’ย ๐‘Ÿ๐‘Ž๐‘›๐‘˜ย ๐‘œ๐‘“ย ๐‘Ž๐‘›ย ๐‘šย ร—ย ๐‘›ย ๐‘š๐‘Ž๐‘ก๐‘Ÿ๐‘–๐‘ฅย ๐ดย ๐‘กโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘›๐‘œ๐‘กย ๐‘ ๐‘ž๐‘ข๐‘Ž๐‘Ÿ๐‘’?ย Question 10Select one:ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย =ย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย โ‰คย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)ย ย ๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย =ย ๐‘š๐‘Ž๐‘ฅ(๐‘š,ย ๐‘›)๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย โ‰ฅย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)

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Solution

๐‘…๐‘Ž๐‘›๐‘˜(๐ด)ย =ย ๐‘š๐‘–๐‘›(๐‘š,ย ๐‘›)

Similar Questions

Given that๐‘“(๐‘ฅ)=2๐‘ฅโˆ’3 and ๐‘”(๐‘ฅ)=1โˆ’๐‘ฅ4solve (๐‘“โˆ˜๐‘”โˆ’1)(๐‘ฅ)=(๐‘“โˆ˜๐‘”)(๐‘ฅ).

Let ๐‘“๐‘“(๐‘–๐‘–, ๐‘—๐‘—) = ๐‘–๐‘– ๐‘—๐‘—๐‘—๐‘—!(a) Calculate ๐‘“๐‘“(2,3).(b) Calculate โˆ‘ ๐‘“๐‘“(2, ๐‘—๐‘—)2๐‘—๐‘—=0 , โˆ‘ ๐‘“๐‘“(๐‘–๐‘–, 3)3๐‘–๐‘–=1 .(c) Calculate โˆ‘ โˆ‘ ๐‘“๐‘“(๐‘–๐‘–, ๐‘—

Find ๐‘“๐‘ฅ and ๐‘“๐‘ฆ for ๐‘“(๐‘ฅ,๐‘ฆ)=(1+๐‘ฅโˆ’๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ Question 9Select one: a. ๐‘“๐‘ฅ=(โˆ’1โˆ’2๐‘ฅ+๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ,๐‘“๐‘ฆ=(3โˆ’4๐‘ฅ+2๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ. b. ๐‘“๐‘ฅ=(2+๐‘ฅโˆ’2๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ,๐‘“๐‘ฆ=(2๐‘ฅโˆ’4๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ. c. None of these d. ๐‘“๐‘ฅ=(2+๐‘ฅโˆ’๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ,๐‘“๐‘ฆ=(1+2๐‘ฅโˆ’2๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ. e. ๐‘“๐‘ฅ=(โˆ’๐‘ฅ+๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ,๐‘“๐‘ฆ=(3โˆ’2๐‘ฅ+2๐‘ฆ)๐‘’๐‘ฅ+2๐‘ฆ.

Q1. Let ๐ด = {0,1,2,3,4,5,6,7} suppose ๐‘… ๐‘Ž๐‘›๐‘‘ ๐‘‡ are two relations on ๐ด such that ๐‘… = {(๐‘ฅ, ๐‘ฆ): ๐‘ฅ + 2๐‘ฆ โ‰ฅ 4}, ๐‘‡ = {(๐‘ฅ, ๐‘ฆ): 2๐‘ฅ + 3๐‘ฆ โˆˆ ๐ด} Write ๐‘…, ๐‘‡, ๐‘Ž๐‘›๐‘‘ ๐‘…ยฐ๐‘‡

If lim๐‘ฅโ†’2๐‘“(๐‘ฅ)=3๐‘ฅ and lim๐‘ฅโ†’2๐‘”(๐‘ฅ)=4๐‘ฅ2โˆ’5, what is lim๐‘ฅโ†’2๐‘”(๐‘“(๐‘ฅ))?

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