why? #AlwaysAskWhyBecause this will be the first opened file descriptor and we start counting starting from 1Because this will be the first opened file descriptor and in CS we start counting starting from 0Because most of the time, I will already have stdin (value 0), stdout (value 1) and stderr (value 2) opened when my program starts executing.I don’t care I never ask why, just let me access the tasks!Because this will be the second opened file descriptor for my processBecause this will be the third opened file descriptor for my process
Question
why? #AlwaysAskWhyBecause this will be the first opened file descriptor and we start counting starting from 1Because this will be the first opened file descriptor and in CS we start counting starting from 0Because most of the time, I will already have stdin (value 0), stdout (value 1) and stderr (value 2) opened when my program starts executing.I don’t care I never ask why, just let me access the tasks!Because this will be the second opened file descriptor for my processBecause this will be the third opened file descriptor for my process
Solution
The reason is that this will be the first opened file descriptor and we start counting starting from 1. This is because it will be the first opened file descriptor and in CS we start counting starting from 0. Additionally, most of the time, stdin (value 0), stdout (value 1), and stderr (value 2) will already be opened when the program starts executing. However, if you don't care about the reason, you can simply access the tasks. If you need to know the specific reason, it is because this will be the second opened file descriptor for your process. Alternatively, it could be the third opened file descriptor for your process.
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