A solenoid has core of a material with relative permeability 500 and its windings carry a current of 1 A. The number of turns of thesolenoid is 500 per metre. Then find magnetization of the material
Question
A solenoid has core of a material with relative permeability 500 and its windings carry a current of 1 A. The number of turns of thesolenoid is 500 per metre. Then find magnetization of the material
Solution
The magnetization of a material (M) is given by the formula:
M = (μr - 1) * H
where μr is the relative permeability and H is the magnetic field strength.
The magnetic field strength (H) inside a solenoid is given by the formula:
H = n * I
where n is the number of turns per meter and I is the current.
Given that μr = 500, n = 500 turns/meter, and I = 1 A, we can substitute these values into the formulas.
First, calculate H:
H = n * I = 500 turns/meter * 1 A = 500 A/m
Then, substitute H and μr into the formula for M:
M = (μr - 1) * H = (500 - 1) * 500 A/m = 249500 A/m
So, the magnetization of the material is 249500 A/m.
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