Given a resistive divider with R1 = 10kΩ and R2 = 5kΩ connected to a 10V source, what is the node voltage between R1 and R2? (Assume ideal conditions) *5 pointsA) 2VB) 3.33VC) 5VD) 6.67V
Question
Given a resistive divider with R1 = 10kΩ and R2 = 5kΩ connected to a 10V source, what is the node voltage between R1 and R2? (Assume ideal conditions) *5 pointsA) 2VB) 3.33VC) 5VD) 6.67V
Solution
The voltage divider equation is Vout = Vin * (R2 / (R1 + R2)).
Given: Vin = 10V R1 = 10kΩ R2 = 5kΩ
Substitute the given values into the voltage divider equation:
Vout = 10V * (5kΩ / (10kΩ + 5kΩ)) = 10V * (5 / 15) = 10V * 0.3333 = 3.33V
So, the node voltage between R1 and R2 is 3.33V. Therefore, the correct answer is B) 3.33V.
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