6. How many electrons could be held in the second shell of an atom if the spinquantum number ms could have three values instead of just two?(Hint: Consider the Pauli exclusion principle)A. 12B. 15C. 20D. 24
Question
- How many electrons could be held in the second shell of an atom if the spinquantum number ms could have three values instead of just two?(Hint: Consider the Pauli exclusion principle)A. 12B. 15C. 20D. 24
Solution
The Pauli Exclusion Principle states that no two electrons in an atom can have the same four quantum numbers. The four quantum numbers are the principal quantum number (n), the azimuthal quantum number (l), the magnetic quantum number (ml), and the spin quantum number (ms).
In a normal atom, the spin quantum number (ms) can have two values: +1/2 and -1/2. This means that each orbital (defined by the other three quantum numbers) can hold two electrons.
The second shell of an atom (n=2) contains four orbitals: one 2s orbital and three 2p orbitals. Therefore, under normal circumstances, the second shell can hold 2 electrons per orbital * 4 orbitals = 8 electrons.
However, if the spin quantum number (ms) could have three values instead of just two, then each orbital could hold three electrons instead of two.
Therefore, the second shell could hold 3 electrons per orbital * 4 orbitals = 12 electrons.
So, the answer is A. 12.
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